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MathML

\begin{aligned} ρ_{L} & = \frac{- 1}{{C V}^{2} + 1} \\ ρ_{U} & = 1 \end{aligned}

\begin{align*} \rho _ L & = \frac{-1}{\mr{CV}^2 + 1} \\ \rho _ U & = 1 \end{align*}